Most Common Hit Roulette Numbers
atrain
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- 100 and one million% there are and always are. I wrote two books on roulette, decoding roulette and gold mining the roulette wheel and am writing another book that will prove beyond a shadow of any doubt that there are patterns within the random.
- Similar to the number seven, it is also popular amongst roulette players. Numbers 23 and 24: also located in the middle of the table and many players also prefer placing bets on them. Numbers that Hit Most in Roulette: Conclusion. These are the most popular and common numbers when playing roulette.
- The most common roulette numbers. There are 36 (37) numbers on the roulette wheel but some of them are more popular than the others. For example, 7, 17, 23, and 24. The first one doesn’t require an explanation. Seven is considered the lucky number all over the world, so gamblers often bet on it no matter what casino game they choose.
Roulette why your Roulette numbers don't come out - Duration: 3:06. Iceman340h 42,921 views. The secret to cracking roulette. (Magic Numbers 4) - Duration: 1:32. On are properly maintained roulette wheel, all numbers are equally likely to spin. The only time particular numbers spin more than others is if the wheel is defective.
I am trying to figure out how many spins would u say is it where a number statistically would have to come up
PapaChubby
There is no number of spins that guarantees that a particular number will come up. The probability never goes to 1, it will only approach it.
For 300 spins the probability that a particular number will not show up is (37/38)^300 = 0.0335%. That's pretty small, but not zero. If you repeated this 300 spin experiment 3000 times, you'd only expect to completely miss your number on one of the trials.
For 300 spins the probability that a particular number will not show up is (37/38)^300 = 0.0335%. That's pretty small, but not zero. If you repeated this 300 spin experiment 3000 times, you'd only expect to completely miss your number on one of the trials.
guido111
I am trying to figure out how many spins would u say is it where a number statistically would have to come up
It is all about the degree of certainty.
For a 38 number wheel.
From http://wizardofvegas.com/member/nope27/blog/:
'The below table is for the probability of NOT hitting 'at least 1' number in x spins.
formula used from:http://wizardofodds.com/askthewizard/roulette.html
question #2 at WoO.
Wizards' Example: for 'at least 1' number NOT hitting in 200 spins
Sum i=1 to 37 [(-1)^(i+1) × combin(38,i) × ((38-i)/38)^38] = 16.9845715651245%'
I have expanded the table below from the above blog.
I have also run 1 million spin simulations and have seen many numbers that did not appear in 500 spins.I would say from the table 1000 spins would be a hard one to ever witness.
| spins | prob | 1 in | expected # of spins |
|---|---|---|---|
| 50 | 99.9999975% | . | . |
| 60 | 99.9991% | . | . |
| 70 | 99.967896% | . | . |
| 80 | 99.678210% | . | . |
| 90 | 98.452658% | . | . |
| 100 | 95.339700% | . | . |
| 110 | 89.728676% | . | . |
| 120 | 81.746470% | . | . |
| 130 | 72.133375% | . | . |
| 140 | 61.855739% | . | . |
| 150 | 51.774802% | 1.9 | 290 |
| 160 | 42.490296% | 2.4 | 377 |
| 170 | 34.326903% | 2.9 | 495 |
| 180 | 27.391862% | 3.7 | 657 |
| 190 | 21.649355% | 4.6 | 878 |
| 200 | 16.984572% | 5.9 | 1,178 |
| 210 | 13.249361% | 7.5 | 1,585 |
| 220 | 10.290675% | 9.7 | 2,138 |
| 230 | 7.966128% | 12.6 | 2,887 |
| 240 | 6.151027% | 16.3 | 3,902 |
| 250 | 4.740313% | 21.1 | 5,274 |
| 260 | 3.647758% | 27.4 | 7,128 |
| 270 | 2.803866% | 35.7 | 9,630 |
| 280 | 2.153364% | 46.4 | 13,003 |
| 290 | 1.652705% | 60.5 | 17,547 |
| 300 | 1.267822% | 78.9 | 23,663 |
| 310 | 0.972205% | 102.9 | 31,886 |
| 320 | 0.745304% | 134.2 | 42,935 |
| 330 | 0.571235% | 175.1 | 57,770 |
| 340 | 0.437748% | 228.4 | 77,670 |
| 350 | 0.335412% | 298.1 | 104,349 |
| 360 | 0.256975% | 389.1 | 140,091 |
| 370 | 0.196867% | 508.0 | 187,944 |
| 380 | 0.150810% | 663.1 | 251,973 |
| 390 | 0.115523% | 865.6 | 337,594 |
| 400 | 0.088490% | 1,130.1 | 452,028 |
| 500 | 0.006149% | 16,261.5 | 8,130,771 |
| 600 | 0.000427% | 234,067.2 | 140,440,306 |
| 700 | 0.000030% | 3,369,203.4 | 2,358,442,356 |
| 800 | 0.000002061985% | 48,496,952.1 | 38,797,561,717 |
| 900 | 0.000000143251% | 698,074,378.6 | 628,266,940,697 |
| 1000 | 0.000000009952% | 10,048,215,791.0 | 10,048,215,791,014 |
statman
For some number or other not to come up, I would say the probability is zero. At least one number has to come up.For a particular number not to come up in 300 spins I would agree with PapaChubby: (37/38)^300 = 0.0335%.
For at least one number not to come up, I think that guido111 has a good grip on the problem based on a solution given by the Wizard for the case of 200 spins, however the Wizard's logic may not be easy for everyone to follow. Here is another approach based on counting the ways the balls can be distributed to the numbers.
We assume that both the balls and the numbers are distinguishable. The numbers are distinguishable because they are all different and the balls are distinguished by the order in which they are thrown. There is a function T(m,n) that gives the number of ways that m distinguishable objects may be distributed to n containers such that every container has at least one object. The number of ways of distributing m objects to n containers without restriction is nm so the probability that all numbers will have been hit by at least one ball is T(m,n)/nm. Subtract this from 1 and that is the probability that at least one number will remain unhit. For m = 300 and n = 38 this evaluates to 0.01267822135, which agrees with guido111's result.
It is always possible either for a particular number or for some number or other not to come up based on the inequality T(m,n) < nm.
The T function is discussed in several books on combinatorics. I shall be glad to provide a bibliography if anyone asks.
A fool is someone whose pencil wears out before its eraser does. - Marilyn Vos Savant
FleaStiff
Its similar to that famed 'two people with a common birthday'. With 24 people in a room you have a fifty percent chance, simply because you are not designating one particular date that has to be matched.
Its the same with a roulette wheel, if you don't specify a particular number that must hit then there are lots of spins that can go by and there being some surviving number that is unhit is still quite likely.
Ofcourse I don't want to know what number will NOT hit on that next spin, I want to know what number will hit on that next spin.
Its the same with a roulette wheel, if you don't specify a particular number that must hit then there are lots of spins that can go by and there being some surviving number that is unhit is still quite likely.
Ofcourse I don't want to know what number will NOT hit on that next spin, I want to know what number will hit on that next spin.
boymimbo
If you were to use the binomial distribution to approximate the answer over 300 spins, the answer would be 38 x (37/38)^300 = .012742You are using a different (correct) formula to account for all possibilities.
----- You want the truth! You can't handle the truth!
mrjjj
(lol) I dont need to look at a chart, I do all the work on my own. TRIAL & ERROR.
I use to play a method (it did quite well for sometime), I tracked all numbers until only ONE left unhit. When I got to that point, I started a 110 progression on that one number. It was around a $3,600 BR. Like I said, I made ALOT of money BUT as usual, it slowly tanked. The 110 combined with how far back it last hit was well over 300 spins and on multiple occasions I might add so I stopped playing it. That particular method slowly lured me away from playing sleepers/due.
Ken
I use to play a method (it did quite well for sometime), I tracked all numbers until only ONE left unhit. When I got to that point, I started a 110 progression on that one number. It was around a $3,600 BR. Like I said, I made ALOT of money BUT as usual, it slowly tanked. The 110 combined with how far back it last hit was well over 300 spins and on multiple occasions I might add so I stopped playing it. That particular method slowly lured me away from playing sleepers/due.
Ken
Most Common Hit Roulette Numbers Generator
Keyser
That's why several gambler's like you have become victims of the 'gambler's fallacy'.
mrjjj
Most Common Hit Roulette Numbers Games
That's why several gambler's like you have become victims of the 'gambler's fallacy'.
.......and you Keyser are low on gas, better stop. Which city this week? I heard the 21/33 is hitting ALOT at a casino in Tucson. Pack up the car and away you go!! (LMAO) Talk about putting all your eggs in ONE basket.
Most Common Hit Roulette Numbers List
KenKeyser
Most Common Roulette Numbers That Hit
There's no difference between a cold number sleeping and a hot number if there are no biased wheels. It's simply gambler's fallacy to believe otherwise.